public class TwoThreads { 
private static Object resource = new Object（）； 
private static void delay（long n） { 
try { Thread.sleep（n）； } 
catch （Exception e） { System.out.print（”Error “）； } 
} 
public static void main（String[] args） { 
System.out.print（”StartMain “）； 
new Thread1（）.start（）； 
delay（1000）； 
Thread t2 = new Thread2（）； 
t2.start（）； 
delay（1000）； 
t2.interrupt 
delay（1000）； 
System.out.print（”EndMain “）； 
} 
static class Thread 1 extends Thread { 
public void run（） { 
synchronized （resource） { 
System.out.print（”Startl “）； 
delay（6000）； 
System.out.print（”End1 “）； 
} 
} 
} 
static class Thread2 extends Thread { 
public void run（） { 
synchronized （resource） { 
System.out.print（”Start2 “）； 
delay（2000）； 
System.out.print（”End2 “）； 
} 
} 
} 
} 
Assume that sleep（n） executes in exactly m milliseconds， and all other code executes in an insignificant amount of time. What is the output if the main（） method is run？（） 

public class TestOne implements Runnable { 
public static void main （String[] args） throws Exception { 
Thread t = new Thread（new TestOne（））； 
t.start（）； 
System.out.print（”Started”）； 
t.join（）； 
System.out.print（”Complete”）； 
} 
public void run（） { 
for （int i= 0； i< 4； i++） { 
 System.out.print（i）； 
} 
} 
} 
What can be a result？（）